“if __name__ == “__main__”: ^ Syntaxerror: Invalid Syntax”

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Thanks for the help.but when I try running that code I get a SyntaxError: invalid syntax at line 11. You don’t save the original file name so there is no "copy from" name. Be sure to back up the.

print ‘n’ + url if __name__ == ‘__main__’: main() The code as given won’t work; the indentation is all off. Here is the program with what I presume is the correct indentation:` import getopt import.

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When I try to check the syntax it gives me an error on the very last line of code. The error "SyntaxError:invalid syntax (line 119, offset 26):a.getWallpaperList()[/pre].

When handling command-line arguments, I roughly know getopt will work. print "a=", a print "b=", b print "c=", c #execute upon command-line invocation if __name__=="__main__": main() You must debug.

Here is the function call: if text in translate._languages: msg = "You have chosen the " + translate._languages[text] global NewLang newlang = LANGUAGE(text) NewLang = newlang.Set() blip.CreateChild().

step 2 148 dumpit() # step 3 149 150 151 # main begins here 152 if __name__ == ‘__main__’: doit(sys.argv) In lines 7-8 I create YEA and NAY, because Python, like C, doesn’t have intuitive names for.

step 2 148 dumpit() # step 3 149 150 151 # main begins here 152 if __name__ == ‘__main__’: doit(sys.argv) In lines 7-8 I create YEA and NAY, because Python, like C, doesn’t have intuitive names for.

print ‘n’ + url if __name__ == ‘__main__’: main() The code as given won’t work; the indentation is all off. Here is the program with what I presume is the correct indentation:` import getopt import.

When handling command-line arguments, I roughly know getopt will work. print "a=", a print "b=", b print "c=", c #execute upon command-line invocation if __name__=="__main__": main() You must debug.